Yesterday, I came across an interesting question on StackOverflow. The question is as follows: assuming you have a sorted array, is it possible to increment locations by 1 (one at a time) and still ensure that the array is sorted in O(1)? Assuming you are not allowed to use any other secondary data-structures, the answer is no. This becomes evident when you have repeated values. Assume a degenerate case where you have an array of identical values; let’s say [0, 0, 0, 0, 0]. If you increment the value in location 0, you now have [1, 0, 0, 0, 0]. For this array to be sorted, the value 1 must be moved to the end of the array (index 4). This will require four comparisons, which means that this will inevitably turn into an O(n) algorithm.
How can we do better?